Electronic Devices - Power Amplifiers - Discussion
Discussion Forum : Power Amplifiers - General Questions (Q.No. 51)
51.
A class A amplifier with RC = 3.3 k
and RE = 1.2 k has a VCC = 20 V. Find IC(sat).
and RE = 1.2 k has a VCC = 20 V. Find IC(sat).Discussion:
2 comments Page 1 of 1.
M. Ahsan Tufail said:
9 years ago
Option B is correct.
Ic (sat) = Vcc/Rc.
Ic (sat) = 20/3.3.
Then, Ic (sat) = 6.1 mA.
Ic (sat) = Vcc/Rc.
Ic (sat) = 20/3.3.
Then, Ic (sat) = 6.1 mA.
Kuheli R. Barman said:
9 years ago
Since, at saturation region, Vcc = 0 V, so Vcc will drop across Rc and RE only.
here, Rc + RE = 3.3 k ohm + 1.2 k ohm,
= 4.5 k ohm,
Ic(sat) = Vcc/(4.5 k ohm),
= 20/(4.5 k ohm) = 4.44 mA.
here, Rc + RE = 3.3 k ohm + 1.2 k ohm,
= 4.5 k ohm,
Ic(sat) = Vcc/(4.5 k ohm),
= 20/(4.5 k ohm) = 4.44 mA.
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