Electronic Devices - Operational Amplifiers - Discussion
Discussion Forum : Operational Amplifiers - General Questions (Q.No. 18)
18.
Refer to the given figure. Calculate the bandwidth.
Discussion:
10 comments Page 1 of 1.
Rahul said:
1 decade ago
Gain bandwidth product (GBP) =gain*corresponding frequency.
And bandwidth= GBP/gain.
So GBP=50*200000.
And.
As it is a non inverting amplifier it's gain= (-Rf/R1).
That is equal to -120.
So bandwidth = (GBP/gain).
83333 Hz.
And bandwidth= GBP/gain.
So GBP=50*200000.
And.
As it is a non inverting amplifier it's gain= (-Rf/R1).
That is equal to -120.
So bandwidth = (GBP/gain).
83333 Hz.
Tonyben said:
10 years ago
It is an inverting amplifier.
A = (1+Rf/Ri).
BW = GBP/A.
BW = 50*200,000/[1+(1.2M/10K)].
BW = APPROXIMATE = 83.33Khz.
A = (1+Rf/Ri).
BW = GBP/A.
BW = 50*200,000/[1+(1.2M/10K)].
BW = APPROXIMATE = 83.33Khz.
Bala said:
1 decade ago
The bandwidth increases by (1+ab) times where a = open loop gain and b = feedback factor.
Ann said:
8 years ago
Inverting amplifier
A=(-Rf/Ri).
Non-Inverting amplifier
A = (1 + Rf/Ri).
A=(-Rf/Ri).
Non-Inverting amplifier
A = (1 + Rf/Ri).
Hannah said:
9 years ago
I can't understand this. Please, can anyone explain me clearly?
Shubham said:
1 decade ago
How to calculate the bandwidth from given circuit?
Sherry said:
1 decade ago
@Rahul.
It is an inverting amplifier.
It is an inverting amplifier.
(1)
Naren said:
1 decade ago
How to calculate?
I need formula?
I need formula?
Ghanshyam yadav said:
1 decade ago
Please explain it.
Explain it said:
1 decade ago
Explain it.
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