Electronic Devices - Op-Amp Applications - Discussion

Discussion Forum : Op-Amp Applications - General Questions (Q.No. 14)
14.
Calculate the cutoff frequencies of a bandpass filter with R1 = R2 = 5 k and C1 = C2 = 0.1 F.
fOL = 318.3 Hz, fOH = 318.3 Hz
fOL = 636.6 Hz, fOH = 636.6 Hz
fOL = 318.3 Hz, fOH = 636.6 Hz
fOL = 636.6 Hz, fOH = 318.3 Hz
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
5 comments Page 1 of 1.

Gaurav pandey said:   9 years ago
R1 = R2,
C1 = C2,
So higher and lower cut-off frequencies are same.

Saurabh said:   9 years ago
@Seema Rajput.

It's pie.

Seema Rajput said:   9 years ago
What is the value of I?
(1)

Ammad Hafeez (RG) said:   1 decade ago
It's simple.

Cutoff frequency = 1/2*I*R*C.

= 318.309 Hz.

Both frequencies will be same.
(1)

Mallik said:   1 decade ago
For a high and low pass filter the cut-off frequencies are given out in the following way f(3db)=1/[RC*2π]

Hence the Fol = 318.3=Foh.

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