Electronic Devices - Op-Amp Applications - Discussion
Discussion Forum : Op-Amp Applications - General Questions (Q.No. 25)
25.
Calculate IL for this circuit.
Discussion:
3 comments Page 1 of 1.
Praveen Tiwari said:
1 decade ago
IL = -Vo/4k ;
Vo = -(4k/2k)*10v;
IL = (20/4K) = 5 mA
Vo = -(4k/2k)*10v;
IL = (20/4K) = 5 mA
Astha rani said:
10 years ago
Here il = i1 means input current is equal to load current.
And input current = v/R = 10k/2 = 5 mA. So il = 5 mA.
And input current = v/R = 10k/2 = 5 mA. So il = 5 mA.
(2)
Ronika singhania said:
5 years ago
Vo = {-4/2}*10.
= - 20 mV .
IL =?
IL = V/R.
= -20/4.
= -5mA.
= - 20 mV .
IL =?
IL = V/R.
= -20/4.
= -5mA.
(1)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers