Electronic Devices - Op-Amp Applications - Discussion
Discussion Forum : Op-Amp Applications - General Questions (Q.No. 24)
24.
Calculate the output voltage Vo if V1 = –V2 = 300 mV.
Discussion:
6 comments Page 1 of 1.
Kenny said:
10 years ago
Why is it 6V, is should be 0 to be?
(1)
Bagus hari antoro said:
8 years ago
I agree if the answer is 0 (zero), because in the last of the stage is (-) so the result is 3-3 = 0.
(1)
Virendra Prajapati said:
1 decade ago
Ans must be 6V because after first stage of amplification on first terminal we get -.6V and 2nd terminal we have 300mV and it acts like summer. Then out at last stage
(500k/50k*(-300m))+(500k/100k*(-.6)=6V
(500k/50k*(-300m))+(500k/100k*(-.6)=6V
Caleb said:
9 years ago
((-500/100) * (-.6)) + ((-500/50) * (-.3)) = 6V.
Anzel Aguirre said:
7 years ago
((-500e3/100e3) * (-0.6))+((-500e3/50e3)*(-300e-3))= 6;
V2 is equal to -300milli. So the answer is 6.
V2 is equal to -300milli. So the answer is 6.
Shahab said:
3 years ago
For inverting amp.
Vo = -Rf/Rin*Vin.
Vo = - (500k/250k) *300mv=-0.6v.
So the second one is summing amplifier.
Vo = (Rf/Rin*V1+Rf/Rin*V2).
-Vo = (500k*/100k* (-0.6) + (500k/50k* (-0.3) = 6v.
Vo = -Rf/Rin*Vin.
Vo = - (500k/250k) *300mv=-0.6v.
So the second one is summing amplifier.
Vo = (Rf/Rin*V1+Rf/Rin*V2).
-Vo = (500k*/100k* (-0.6) + (500k/50k* (-0.3) = 6v.
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