Electronic Devices - Op-Amp Applications - Discussion
Discussion Forum : Op-Amp Applications - General Questions (Q.No. 10)
10.
Calculate the input voltage if the final output is 10.08 V.
Discussion:
6 comments Page 1 of 1.
Abhilash said:
7 years ago
Good explanations. Thanks to all.
Jayzeebeee said:
8 years ago
Take input as x:
So the equation becomes;
10/5*x+2x*100/5=>2x+2x*20=10.08.
so x=10.08/80=0.168.
So the equation becomes;
10/5*x+2x*100/5=>2x+2x*20=10.08.
so x=10.08/80=0.168.
Asdf said:
8 years ago
Explanation is awesome, thank you @Mallik.
Sonam said:
1 decade ago
Vo = (1+10k/5k) * (-5k/5k) * (-100k/5k) V1.
Vo = 3 * -1 * -20 V1.
V1 = 10.08 / 60.
V1 = 0.168.
Vo = 3 * -1 * -20 V1.
V1 = 10.08 / 60.
V1 = 0.168.
(2)
Mallik said:
1 decade ago
Keep in mind that there are two inverting and one non-inverting amplifiers.. gain of whole system is G= G1*G2*G3
G1 non-inverting
G= (1+10k/5k)*(-5k/5k)*(100k/5k)
Vout/Vin=60;
=> Vin= 0.168;
G1 non-inverting
G= (1+10k/5k)*(-5k/5k)*(100k/5k)
Vout/Vin=60;
=> Vin= 0.168;
(1)
Suresh nagaraj said:
1 decade ago
Vo/Vin=(1+Rf1/R1)*(-Rf2/R2)*(-Rf3/R3)
10.08/Vin=2*1*30
Vin=0.168 V
10.08/Vin=2*1*30
Vin=0.168 V
(1)
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