# Electronic Devices - Field-Effect Transistors - Discussion

Discussion Forum : Field-Effect Transistors - General Questions (Q.No. 3)
3.

Refer to figure given below. Calculate the value of VDS.

0 V
2 V
4 V
–2 V
Explanation:
No answer description is available. Let's discuss.
Discussion:
10 comments Page 1 of 1.

Marki said:   1 year ago
@Kvl.

20 - Id (1K+2K) -Vs =0.
Vds = 2V.
Or Vs = Id (1k+2k) = 18.
Vds = Vd-Vs = 20-18 = 2V.

Chinnu said:   5 years ago

Katekyo said:   7 years ago
It's a JFET so basically, if there is no voltage applied to the Gate then the source-to-drain path is complete and will be operating.

Priyanka said:   9 years ago
It must be 0v because drain to source path is not completed as we are not giving supply to the gate.

Apply KVL to outer circuit we get the required value.

Well to find out voltage drop across rs one should apply the voltage division formula. It says. R1(apposite value resistor)/r1+r2 *current flowing through them.

KAVITA RATHORE said:   1 decade ago
vdd-[ID(RD+RS)]=20-[6mA(3K)]=20-18=2V