Electronic Devices - Field-Effect Transistors - Discussion
Discussion Forum : Field-Effect Transistors - General Questions (Q.No. 11)
11.
Refer to figure given below. Determine the value of VGS.
Discussion:
8 comments Page 1 of 1.
Vani said:
8 years ago
You said that vds=[id(rd+rs)] by this answer becomes 2v then it becomes -6v.
Can you give correct formula for vds.
Can you give correct formula for vds.
Kobi said:
9 years ago
Applying kvl:
Ig * Rg + Vgs + Id * Rs = 0
Ig = 0 cause there is no current flowing into the gate.
Vgs= - 6m * 1k = -6V.
Ig * Rg + Vgs + Id * Rs = 0
Ig = 0 cause there is no current flowing into the gate.
Vgs= - 6m * 1k = -6V.
Khagendra joshi said:
1 decade ago
For more clarification on negative sign, directly apply kvl on gate source loop.
Rakesh said:
1 decade ago
Why -ve sign?
Saidulu said:
1 decade ago
Apply kvl across gate and drain.
Kirupa said:
1 decade ago
Formula is Vgs= -(Id*Rs)
(1)
Kirupa said:
1 decade ago
Vgs= -(Id*Rs)
Varun said:
1 decade ago
Because vgs= -vs.
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