Electronic Devices - Field-Effect Transistors - Discussion
Discussion Forum : Field-Effect Transistors - General Questions (Q.No. 6)
6.
Refer to the given figure. ID = 6 mA. Calculate the value of VDS.
Discussion:
3 comments Page 1 of 1.
Julio said:
6 years ago
When the D-MOSFET is P-channel, VDS is always negative?
Deepika Uniyal said:
6 years ago
Vds = -15-ID*rd.
= -15-(-6 *-1),
= -9volt.
= -15-(-6 *-1),
= -9volt.
(1)
Pavan said:
1 decade ago
In general Vds= Vdd-(Id*Rd)
But in figure direction of FET transistor is out of drain so, Id becomes negative .
ie, Vds=Vdd-(-Id*Rd)
Vds=-15-(-6ma*1k)
= -9v
But in figure direction of FET transistor is out of drain so, Id becomes negative .
ie, Vds=Vdd-(-Id*Rd)
Vds=-15-(-6ma*1k)
= -9v
(1)
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