Electronic Devices - FET Amplifiers - Discussion
Discussion Forum : FET Amplifiers - General Questions (Q.No. 5)
5.
Refer to this figure. Find the value of VD.
Discussion:
11 comments Page 1 of 2.
Srawan said:
4 years ago
@Dev
Can you explain, that in 0.3 Vp how it became I'd = Idss/2?
Can you explain, that in 0.3 Vp how it became I'd = Idss/2?
Dev said:
6 years ago
Id=Idss /2 is only possible when Vgs=0.3Vp.
(1)
Kris said:
7 years ago
First, you can see the symbol that its clearly a n-type JFEt. Second, At Vgs equal to zero, Id is Idss. Not Idss/2.
Tinsot said:
7 years ago
The circuit shown is a zero biased amplifier therefore VGS is zero. This is a D MOSFET I think. At Vgs equals to zero, Id=Idss/2.
Baby electron said:
8 years ago
Thank you all for explaining the problem.
Nandu said:
9 years ago
It was get by using py model or hybrid model.
id = gm*vgs.
Vgs = idss*(i/p resistance).
id = gm*vgs.
Vgs = idss*(i/p resistance).
Titir said:
10 years ago
I also have doubt regarding this answer.
Yamini said:
1 decade ago
How can say that ID=ISS/2? Here VGS or VP is not mentioned.
Shahid said:
1 decade ago
VD = VDD-IDRD.
ID = IDSS/2 = 10mA/2 = 5mA.
VD = 20-(5)(2.2).
VD = 20-11.
VD = 9.
ID = IDSS/2 = 10mA/2 = 5mA.
VD = 20-(5)(2.2).
VD = 20-11.
VD = 9.
(1)
Shripada said:
1 decade ago
I didn't get how this answer came? explain me.
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