# Electronic Devices - FET Amplifiers - Discussion

Discussion Forum : FET Amplifiers - General Questions (Q.No. 5)
5.

Refer to this figure. Find the value of VD.

20 V
11 V
10 V
9 V
Explanation:
No answer description is available. Let's discuss.
Discussion:
11 comments Page 1 of 2.

Srawan said:   3 years ago
@Dev

Can you explain, that in 0.3 Vp how it became I'd = Idss/2?

Dev said:   6 years ago
Id=Idss /2 is only possible when Vgs=0.3Vp.
(1)

Kris said:   6 years ago
First, you can see the symbol that its clearly a n-type JFEt. Second, At Vgs equal to zero, Id is Idss. Not Idss/2.

Tinsot said:   6 years ago
The circuit shown is a zero biased amplifier therefore VGS is zero. This is a D MOSFET I think. At Vgs equals to zero, Id=Idss/2.

Baby electron said:   7 years ago
Thank you all for explaining the problem.

Nandu said:   8 years ago
It was get by using py model or hybrid model.

id = gm*vgs.

Vgs = idss*(i/p resistance).

Titir said:   9 years ago
I also have doubt regarding this answer.

Yamini said:   10 years ago
How can say that ID=ISS/2? Here VGS or VP is not mentioned.

Shahid said:   10 years ago
VD = VDD-IDRD.
ID = IDSS/2 = 10mA/2 = 5mA.

VD = 20-(5)(2.2).
VD = 20-11.

VD = 9.