Electronic Devices - Diode Applications - Discussion
Discussion Forum : Diode Applications - General Questions (Q.No. 5)
5.
What is the voltage measured from the negative terminal of C4 to the negative terminal of the transformer?
Discussion:
18 comments Page 1 of 2.
Anjali said:
9 years ago
@Sreenu.
Thanks for explaining in an easy method.
Thanks for explaining in an easy method.
Sreenu said:
9 years ago
It is very simple.
There are 4 loops, in each loop capacitor charges up to voltage to 5v and for 4 loops it will be 20v.
And we are measuring the voltage across the negative terminal it would be - 20v.
And it is quadruple circuit or two voltage doubler circuits connected in series.
There are 4 loops, in each loop capacitor charges up to voltage to 5v and for 4 loops it will be 20v.
And we are measuring the voltage across the negative terminal it would be - 20v.
And it is quadruple circuit or two voltage doubler circuits connected in series.
Haren said:
10 years ago
C1 charges to Vm, through D1, C2 charges through D2, C3 and C4 charges through D4, C2, C3 and C4 charges to 2Vm. The 4Vm output is taken across C2 and C4.
Divya sree said:
1 decade ago
Ok I want what is the voltage at c2?
(1)
Oscar Amaefula said:
1 decade ago
A voltage doubler is an electronic circuit which charges capacitors from the input voltage and switches these charges in such a way that, in the ideal case, exactly twice the voltage is produced at the output as at its input.
Karthick.v said:
1 decade ago
What is voltage quarter explain?
Chetan said:
1 decade ago
How answer comes out to be -20 why not 20? Please explain.
Monicka said:
1 decade ago
What is meant by voltage doubler?
Sumanta said:
1 decade ago
Consider this as two voltage doubler. For +5V C1 does not charge. But C2 charges to -5 V. So the negative potential becomes -10V. Now consider the second half with -10V source. Similarly C3 does not charge but C4 charges to -20 V (-10 + (-10V) <- charged capacitor).
Capacitor is charged with current flow - to +. Which is not possible for odd indexed capacitors :-).
Capacitor is charged with current flow - to +. Which is not possible for odd indexed capacitors :-).
Avnish sharma said:
1 decade ago
What is the working of quadrupples?
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