Electronic Devices - Diode Applications - Discussion
Discussion Forum : Diode Applications - General Questions (Q.No. 9)
9.
Determine the peak value of the output waveform.
Discussion:
13 comments Page 1 of 2.
Millize said:
4 years ago
@All.
Here assume that the diode is ideal hence no voltage drop of 0.7 V and the answer would be 15 V.
Also it is not in reverse bias since there is the voltage appearing across the anode is 20V-5V = 15 V it would be forward biased.
Here assume that the diode is ideal hence no voltage drop of 0.7 V and the answer would be 15 V.
Also it is not in reverse bias since there is the voltage appearing across the anode is 20V-5V = 15 V it would be forward biased.
(1)
Nirali said:
5 years ago
In the ideal condition of the diode, we do need to 0.7 volt of the diode. that's why 15v is the answer.
Emengrrr said:
7 years ago
The diode is forward bias in the positive cycle but reverse in the negative cycle.
I think it must be 14.3V or if making the diode ideal, it will result to 15V.
I think it must be 14.3V or if making the diode ideal, it will result to 15V.
Rajan said:
7 years ago
@Jamar.
But the input voltage is greater in magnitude than the battery. The diode will still be forward-biased.
But the input voltage is greater in magnitude than the battery. The diode will still be forward-biased.
Jamar said:
7 years ago
The negative side of the battery is on the positive side of the diode. That's why it is in reverse bias.
Blk said:
7 years ago
@Singh.
How is it in reverse bias?
How is it in reverse bias?
Singh said:
10 years ago
Diode is in reverse bias. So diode voltage won't be taken into account.
(1)
Sihle said:
1 decade ago
But then how is that possible, cause we having Vbias in series with the diode, are not suppose to have an expression like 20-(Vbias-0.7V).
Dyab dabbeek said:
1 decade ago
I agree with Ashu because the diode has voltage 0.7v so that:
20-5 - 0.7 = 14.3v.
20-5 - 0.7 = 14.3v.
Ashu said:
1 decade ago
Sir, we need to consider diode vtg as well which is 0.7V constant. So the answer is 20-5-0.7 = 14.3V.
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