Electronic Devices - Diode Applications - Discussion
Discussion Forum : Diode Applications - General Questions (Q.No. 22)
22.
Determine ID2.
Discussion:
7 comments Page 1 of 1.
Asasj said:
2 years ago
since Ge Diode is equal, we can divide I total to 2.
First, get their total current by KVL.
10(0.33K)-(0.3V)(0.33K)= 29.394mA.
then, ID2 = Itotal/2 = 12.7mA.
First, get their total current by KVL.
10(0.33K)-(0.3V)(0.33K)= 29.394mA.
then, ID2 = Itotal/2 = 12.7mA.
(1)
SREEKALA.K.S said:
1 decade ago
TOTAL CURRENT I=ID1+ID2
I=(10 - 0.3)/0.33K = 29.3939
HERE BOTHA ARE GE DIODE SO ID1=ID2
ID2=I/2 = 14.5
I=(10 - 0.3)/0.33K = 29.3939
HERE BOTHA ARE GE DIODE SO ID1=ID2
ID2=I/2 = 14.5
(2)
Gunjan said:
1 decade ago
TOTAL CURRENT I = ID2+ID1
I=(10-0.7)/0.33 = 28.1818
HERE BOTH ARE SI DIODE SO ID1=ID2
ID2=I/2=14.1969
I=(10-0.7)/0.33 = 28.1818
HERE BOTH ARE SI DIODE SO ID1=ID2
ID2=I/2=14.1969
Emengir said:
7 years ago
If one is Si and the other is Ge, the current only flows to the Ge.
JOEL said:
1 decade ago
I=(10-0.3)=29.393939.
ID2=I/2=14.696969 A.
ID2=I/2=14.696969 A.
(1)
Vishnu said:
8 years ago
What if one is Si and another is Ge?
Nisha said:
7 years ago
Thanks for explaining the answer.
(1)
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