Electronic Devices - Diode Applications - Discussion

Here an ideal diode is used & If we consider the diode is Ge whose voltage drop 0.3v and Si whose voltage drop 0.7 then the applied voltage is comparatively very low which is 0.2v.

So no current will pass through the diode.... so it's 0v..

Since is diode is RB in the given arrangement so the current flowing in the circuit is zero and hence the voltage drop across are is zero.

Ideal diode drops 0 volts, hence diode is forward bias so current flows.

The voltage is 0 due to the diode is forward bias & the supply voltage is DC which fed to the diode.

Don't know what's the issue. But as the diode is Forward Biased, the circuit is shorted. As analyzed by pSpice. And hence the voltage through is 0.001967V.

@Sumanta you are correct.

I think the no voltage across the resistor because the supply voltage is only 0.2v with that cannot trigger the barrier potential 0.7v and we know that in a solving like this we use the 2nd approximation so, we will include the 0.7v knee voltage in this problem. and also, the problem doesn't state that it is an ideal diode. So we assume automatically that it is 2nd approximation to be used.