Electronic Devices - DC Biasing-FETs - Discussion
Discussion Forum : DC Biasing-FETs - General Questions (Q.No. 2)
2.
Calculate the value of VDS.
Discussion:
6 comments Page 1 of 1.
Severina said:
3 years ago
We know that in FET, Ig = 0.
1. Vgs = 8 V.
2. By Shockley's equation (make sure that Vgs and Vp have equal signs).
Id=Idss (1- (Vgs/Vp) ) ^2.
Id = 10m (1- (-8/-80) ^2.
Id = 0.
3. By KVL on the right side,
-16 + 2 (Id) + Vds =0,
-16 + 2 (0) + Vds =0,
Vds = 16 V => answer.
1. Vgs = 8 V.
2. By Shockley's equation (make sure that Vgs and Vp have equal signs).
Id=Idss (1- (Vgs/Vp) ) ^2.
Id = 10m (1- (-8/-80) ^2.
Id = 0.
3. By KVL on the right side,
-16 + 2 (Id) + Vds =0,
-16 + 2 (0) + Vds =0,
Vds = 16 V => answer.
(1)
Rectifier said:
1 decade ago
I agree with @RHYDER.
That's my solution too. Take a loop from gate to source. The 1 Megaohm resistor is shorted so you will get Vgs = -Vgg and Vgg is equal to 8v and add the negative sign so its -8v.
Do the Shockley equation and you will find that ID is equal to zero.
And finally DSloop. Vds = 16v.
That's my solution too. Take a loop from gate to source. The 1 Megaohm resistor is shorted so you will get Vgs = -Vgg and Vgg is equal to 8v and add the negative sign so its -8v.
Do the Shockley equation and you will find that ID is equal to zero.
And finally DSloop. Vds = 16v.
Paseka said:
1 decade ago
When Vgs = Vp.
Then Vds = Vdd.
Then Vds = Vdd.
Vijay said:
1 decade ago
What is Idss?
Why we took Vgs = -8.
As we know: Vp = Vgs(off).
Why we took Vgs = -8.
As we know: Vp = Vgs(off).
Rhyder said:
1 decade ago
KVL@ GS loop...
then Vgs=-8V
then use shockley equation
Id=Idss(1-(Vgs/Vp))^2
Id=0A
then KVL@ DS loop
16V-Id(2K)-Vds=o
Vds=16V
then Vgs=-8V
then use shockley equation
Id=Idss(1-(Vgs/Vp))^2
Id=0A
then KVL@ DS loop
16V-Id(2K)-Vds=o
Vds=16V
Sumit said:
1 decade ago
How can we find?
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