Electronic Devices - DC Biasing-BJTs - Discussion
Discussion Forum : DC Biasing-BJTs - General Questions (Q.No. 7)
7.
Calculate the value of VCEQ.
Discussion:
4 comments Page 1 of 1.
Severina said:
2 years ago
ic = Bib.
ie = (B+1)ib.
1. kvl on the left side.
-18+3.3k(B) (ib) + (91k+110k) Ib + 0.7 + 510 (B+1)ib = 0.
Ib = 35.50 micro A.
2. kvl on the right side.
-18 + 3.3k (Bib) + Vce + 510 (B+1)Ib = 0.
Vce = 7.84 V => answer.
ie = (B+1)ib.
1. kvl on the left side.
-18+3.3k(B) (ib) + (91k+110k) Ib + 0.7 + 510 (B+1)ib = 0.
Ib = 35.50 micro A.
2. kvl on the right side.
-18 + 3.3k (Bib) + Vce + 510 (B+1)Ib = 0.
Vce = 7.84 V => answer.
(3)
Swati singh said:
1 decade ago
From above solution IB = 0.0352mA.
18 = 3*3kohm*IB*(b+1)+VCE+0.510*0.0352*(b+1).
18 = 8.82+VCE+1.36.
VCE = 7.82.
18 = 3*3kohm*IB*(b+1)+VCE+0.510*0.0352*(b+1).
18 = 8.82+VCE+1.36.
VCE = 7.82.
Danee said:
7 years ago
@Janhavi.
Because the circuit is a collector feedback, and the current across it is ib+ic which is equal to ie.
Because the circuit is a collector feedback, and the current across it is ib+ic which is equal to ie.
Janhavi singh said:
9 years ago
Why are we doing 3.3 (b + 1) shouldn't it be 3? 3Beta because ic = Beta Ib.
(2)
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