Electronic Devices - DC Biasing-BJTs - Discussion
Discussion Forum : DC Biasing-BJTs - General Questions (Q.No. 4)
4.
Determine the reading on the meter when VCC = 20 V, RC = 5 k
, and IC = 2 mA.
, and IC = 2 mA. 
Discussion:
5 comments Page 1 of 1.
Mishra said:
9 years ago
Vce = 20 - (5 * 2).
Vce = 20 - 10.
Then, VCE = 10v => answer right.
Vce = 20 - 10.
Then, VCE = 10v => answer right.
Hase BHAGYASHRI said:
1 decade ago
Vce = Vcc - IcRc.
Vce = 20 - 10*10^-3*10*10^3.
vce = 10v.
Vce = 20 - 10*10^-3*10*10^3.
vce = 10v.
Mahak Anurag said:
1 decade ago
Given: Vcc=20v,Ic=5k,Rc=2mA
Voltmeter calculates voltage between Collector & Emitter terminals i.e. Vce.
We know, Vce=Vcc-IcRc
=>Vce=20-(5x2)
=>Vce=20-10
Vce=10v
Voltmeter calculates voltage between Collector & Emitter terminals i.e. Vce.
We know, Vce=Vcc-IcRc
=>Vce=20-(5x2)
=>Vce=20-10
Vce=10v
Prasad said:
1 decade ago
Vce=20-(2m)*5K -20=10 V
Sanjay kumar panda said:
1 decade ago
Vce=Vcc-IcRc
(1)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers