Electronic Devices - DC Biasing-BJTs - Discussion
Discussion Forum : DC Biasing-BJTs - General Questions (Q.No. 8)
8.
For what value of 
does the transistor enter the saturation region?
does the transistor enter the saturation region? 
Discussion:
3 comments Page 1 of 1.
Verice said:
1 decade ago
let Isc= saturation current = Ic
Ic= Isc = 12/2.2k = 5.454mA
Ib = (12 - 0.7)/ 240k = 47.08uA
Beta = Ic/Ib = 5.454mA/47.08uA =115.848 = 116
Ic= Isc = 12/2.2k = 5.454mA
Ib = (12 - 0.7)/ 240k = 47.08uA
Beta = Ic/Ib = 5.454mA/47.08uA =115.848 = 116
(2)
Mur said:
1 decade ago
If rb = 240k it not possible to get this value(240m ohm).
(1)
Nood said:
6 years ago
How B forced is bigger than B DC? I think it should be the opposite.
(2)
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