Electronic Devices - Communications - Discussion
Discussion Forum : Communications - General Questions (Q.No. 7)
7.
For a four-quadrant linear multiplier, what is the output voltage, given input voltages of Vx = +2 V and Vy = –10 V?
Discussion:
4 comments Page 1 of 1.
Mudireddy BalaSubbaReddy said:
1 decade ago
The output Voltage of Four Quadrant Linear Multiplier is
Vo = [ (Vx1-Vx2)*(Vy1-Vy2)/Vref ] +Vz
In general Vref = 10V and in practice Vx2 = Vy2 = Vz = 0V
Therefore Vo=(Vx1*Vy1)/10
= (2V*(-10V))/10
=-2V
Vo=-2V
Vo = [ (Vx1-Vx2)*(Vy1-Vy2)/Vref ] +Vz
In general Vref = 10V and in practice Vx2 = Vy2 = Vz = 0V
Therefore Vo=(Vx1*Vy1)/10
= (2V*(-10V))/10
=-2V
Vo=-2V
Kunal sharma said:
1 year ago
Can anyone explain it in detail?
Madhubala said:
1 decade ago
vo=k*Vx*Vy,where k=0.1
Ankit mayur said:
1 decade ago
vo=a*Vx*Vy{a=0.1}
(1)
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