Electronic Devices - BJT Devices - Discussion

Discussion Forum : BJT Devices - General Questions (Q.No. 16)
16.
Determine the value of when = 100.
1.01
101
0.99
Cannot be solved with the information provided
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
10 comments Page 1 of 1.

Jonathan F said:   8 years ago
Remember that Ie=Ic+Ib.
Then we divide each side by Ic and we will get (1/alpha)=1+(1/beta).
(Since alpha=Ie/Ic and beta=Ic/Ib)

By manipulating the equation.
We will get alpha = beta/(1+beta) then sub 100 to the beta.
Alpha = 0.990099.

Koyyada pushpalatha from gousekonda said:   1 decade ago
Alpha = Beta/(1+Beta).
Alpha = 100.
Alpha = 100/1+100.
Alpha = 100/101.
Alpha = 0.99.
(1)

M.Divya said:   1 decade ago
Alpha= (beta)/(1+beta).

By substituting beta value in above equation.

We get alpha 0.99.

Bhaskar said:   1 decade ago
Beta=1/ (1-alpha).

Priyam said:   1 decade ago
Beta = alfa / (1- alfa)
100 = alfa / (1 - alfa)
alfa = .99

Vinita said:   1 decade ago
It should be noted that alfa is always greater than beta, since collector current is always greater than base current.

(1/alfa)+(1/beta)=1
so alfa=(beta/beta-1)
=100/(100-1)
=100/99
=1.01

Mamta said:   1 decade ago
Since alpha =(beta)/(1+beta)
=100/(1+100)
=100/101
=0.99

LABHESH said:   1 decade ago
WHAT IS FORMULA TO CALCULATE BETA ?

MANIKANDAN said:   1 decade ago
alpha=(beta)/(1+beta)
beta=(alpha)/(1-alpha)

Srikanth said:   1 decade ago
alpha=(beta)/(1+beta)

Post your comments here:

Your comments will be displayed after verification.