Electronic Devices - BJT and FET Frequency Response - Discussion

Discussion Forum : BJT and FET Frequency Response - General Questions (Q.No. 4)
4.
Determine the lower cutoff frequency of this network.

15.8 Hz
46.13 Hz
238.73 Hz
1575.8 Hz
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
11 comments Page 1 of 2.

Kimi said:   4 years ago
Choose Rs and Cs because that is for Low-pass.

And based on the question we need a Low cut-off frequency. so the formula must be 1/(2*π*RC) wherein R=(Rs||(1/gm)).
(1)

Pulls said:   1 decade ago
f = 1/2*pi*(rsi+rg)*cg formula can be used.

Lily said:   8 years ago
RG should be 1M ohms.

Kweku said:   7 years ago
@Pulls.

The formula gives D as answer when RG is taken as 1M ohms.

Paul said:   7 years ago
f=1/2π*Req*Cs.

where:
Req= Rs II 1/gm.

Ans. 238.73.

Paul said:   7 years ago
The cut off frequency at Cs.

f=1/2π*(Rs II 1/gm)*Cs.

John said:   7 years ago
What's the value of gm?

Erwin John said:   6 years ago
@John.

For gm, get the value of current Id first. Use the formula:

Id = Idss (1- (Vgs/Vp))^2 but replace Vgs with -Id(Rs).

Then you will get two values of Id. Choose the lower value which is equal to 2mA.
The lower value of Id means that the FET is operating below the zero bias current, Idss.

Get Vgs using the formula Vgs = -Id(Rs).

And use this formula to get gm.
gm = (2Idss/|Vp|)(1-(Vgs/Vp)).

Abdul haseeb said:   6 years ago
How to calculate gm, Vgs, Id? Explain.

Abdul haseeb said:   6 years ago
How to calculate voltage gain, z input impedance and output impedance?


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