Electronic Devices - BJT Amplifiers - Discussion
Discussion Forum : BJT Amplifiers - General Questions (Q.No. 3)
3.
Which of the h-parameters corresponds to re in a common-base configuration?
Discussion:
7 comments Page 1 of 1.
Ronald Ros said:
2 years ago
In the common-base configuration, the emitter side is the input while the output is the collector (having the base terminal as their ground in both input and output). re refers to the resistance in the emitter so dividing the voltage in the emitter and its current, we can determine the re.
re = Ve/Ie;
The hib refers to the h-parameter in the input of the common-base configuration. It is the ratio between the input voltage and input current. Since the emitter is used as input, hib can be simply addressed as re.
re = Ve/Ie;
The hib refers to the h-parameter in the input of the common-base configuration. It is the ratio between the input voltage and input current. Since the emitter is used as input, hib can be simply addressed as re.
Alec said:
5 years ago
The input of common base is on the emitter side.
The h parameter, hib, means input impedance of base, so the answer is re.
The h parameter, hib, means input impedance of base, so the answer is re.
MAYJOY SIDAYON said:
6 years ago
hib = Vi/Ii, while r'e=26mV/Ie.
They have the same unit.
They have the same unit.
Khan said:
6 years ago
Please can anyone explain this?
Gio said:
6 years ago
What is hib and how is it equal with r sub e? Please explain in detail.
Siri said:
7 years ago
how re equivalent to hib? Explain.
Subbarao said:
8 years ago
What is r base e?
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