Electronic Devices - BJT Amplifiers - Discussion
Discussion Forum : BJT Amplifiers - General Questions (Q.No. 66)
66.
Refer to this figure. If an emitter bypass capacitor was installed, what would the new Av be?
Discussion:
4 comments Page 1 of 1.
Joselito De Castro Jr said:
7 years ago
Here Av= α(RC)/re.
Rajashekar balya said:
8 years ago
Av=Rc/re.
re=25mv/6ma=4.16.
re=25mv/6ma=4.16.
Kaz said:
9 years ago
Low frequency ~-5 Rc/Re + re (re ~4 Ohms).
High frequency ~-600 (as Re is bypassed leaving only Rc/re).
High frequency ~-600 (as Re is bypassed leaving only Rc/re).
Sajjad said:
10 years ago
Answer will be A by using this formula: Rc\re+Re.
(1)
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