Electronic Devices - Bipolar Junction Transistors - Discussion
Discussion Forum : Bipolar Junction Transistors - General Questions (Q.No. 16)
16.
In this circuit 
DC = 100 and VIN = 8 V. The value of RB that will produce saturation is:
DC = 100 and VIN = 8 V. The value of RB that will produce saturation is:
92 k
9.1 M
100 k
150 k
Discussion:
11 comments Page 1 of 2.
Indhu said:
6 years ago
How to calculate Vce value?
Elango said:
7 years ago
Kindly give the explanation for kvl.
Brickoo said:
8 years ago
How to get the Vce saturation?
JENNY said:
8 years ago
When we calculate IC=VC/RC? Can we do whenever need IC this is applicable?
JENNY said:
8 years ago
When we calculate IC=VC/RC?
Can we do whenever need IC this is applicable?
Can we do whenever need IC this is applicable?
Teja said:
9 years ago
Let us assume vcesat = 0.2.
Then apply kcl for output circuit.
20-0.2/2.5 = 7.92mA = ic
ic = bib
ib = ic/b = 7.92/100 = 0.0792.
Then kvl for input side.
8 - 0.7-0.0792 * rb = 0,
rb = 8-0.7/0.0792 = 92kohms.
Then apply kcl for output circuit.
20-0.2/2.5 = 7.92mA = ic
ic = bib
ib = ic/b = 7.92/100 = 0.0792.
Then kvl for input side.
8 - 0.7-0.0792 * rb = 0,
rb = 8-0.7/0.0792 = 92kohms.
(1)
Teja said:
9 years ago
Let us assume vcesat = 0.2.
Then apply kcl for output circuit.
20-0.2/2.5 = 7.92mA = ic
ic = bib
ib = ic/b = 7.92/100 = 0.0792.
Then kvl for input side.
8 - 0.7-0.0792 * rb = 0,
rb = 8-0.7/0.0792 = 92kohms.
Then apply kcl for output circuit.
20-0.2/2.5 = 7.92mA = ic
ic = bib
ib = ic/b = 7.92/100 = 0.0792.
Then kvl for input side.
8 - 0.7-0.0792 * rb = 0,
rb = 8-0.7/0.0792 = 92kohms.
RISHIKESH said:
9 years ago
Ic = α *Ie + Icbo = β * Ib + Icbo.
Ic~alfa * Ie = β * Ib-------> (1)
Ic = (20 - 0.2 ÷ 2.5)mA =7.92mA (since Sat Vce<=0.2v).
Ic = 100 * Ib = >> Ib = 0.0792mA.
Rb = 8-0.7 ÷ Ib -------> (2)
From 1&2
Rb = 92kohm (apox).
Ic~alfa * Ie = β * Ib-------> (1)
Ic = (20 - 0.2 ÷ 2.5)mA =7.92mA (since Sat Vce<=0.2v).
Ic = 100 * Ib = >> Ib = 0.0792mA.
Rb = 8-0.7 ÷ Ib -------> (2)
From 1&2
Rb = 92kohm (apox).
Anirban Bora said:
1 decade ago
The condition for saturation need to be consider that is Vce = 0.2 v.
Then Ic(sat) = (20-0.2)/2.5 = 7.92 mA.
Ib = 7.92/100 = 0. 079 mA.
Now Rb = 8-0.7/0.079 = 92 k(approx).
Then Ic(sat) = (20-0.2)/2.5 = 7.92 mA.
Ib = 7.92/100 = 0. 079 mA.
Now Rb = 8-0.7/0.079 = 92 k(approx).
Sumit said:
1 decade ago
Ic=beta*Ib is condition of active region but given condition is saturation.
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