Electronic Devices - Bipolar Junction Transistors - Discussion
Discussion Forum : Bipolar Junction Transistors - General Questions (Q.No. 11)
11.
Refer to this figure. The value of VCE is:
Discussion:
7 comments Page 1 of 1.
Karthikeya said:
4 years ago
Vce = Vc - Ve.
= 20 - 0.7,
= 19.3.
= 20 - 0.7,
= 19.3.
(1)
Manoj said:
9 years ago
Vce = Vcb + Vbe.
Vcb = 9.2v from ex.6.
Vbe = 0.7v for silicon transistor.
thus,
Vce = 9.9v.
Vcb = 9.2v from ex.6.
Vbe = 0.7v for silicon transistor.
thus,
Vce = 9.9v.
(1)
Atul Mishra said:
1 decade ago
In active mode vbe = 0.7 v.
Then Ib = (5- 0.7)/5k = 0.86 mamp.
Then Ic = 25*0.86 = 21.5.
Then drop across 470 ohm resister = 21.5*0.47 = 10.105 v.
Then voltage at collector = 20-10.105 = 9.89 v that is equal to Vce because emitter bis at ground.
Then Ib = (5- 0.7)/5k = 0.86 mamp.
Then Ic = 25*0.86 = 21.5.
Then drop across 470 ohm resister = 21.5*0.47 = 10.105 v.
Then voltage at collector = 20-10.105 = 9.89 v that is equal to Vce because emitter bis at ground.
Nilesh said:
1 decade ago
Value of vce is 0.7 v.
Kannan M said:
1 decade ago
Vcc= Vce+ IcRc
20=Vce+470Ic
Vbb=Vbe-IbRb
5=0.7-5kIb
4.3/5k=Ib
Ib=0.86mA
B=Ic/Ib
Ic=25*0.86mA
Ic=21.5mA
Vce=20-10.105
Hence Vce = 9.895 Volt
20=Vce+470Ic
Vbb=Vbe-IbRb
5=0.7-5kIb
4.3/5k=Ib
Ib=0.86mA
B=Ic/Ib
Ic=25*0.86mA
Ic=21.5mA
Vce=20-10.105
Hence Vce = 9.895 Volt
(2)
Baye said:
1 decade ago
First find ib by kvl then ic then apply kvl again.
(2)
Mec said:
1 decade ago
Get the value of Vbe=0.7
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