Electronic Devices - Bipolar Junction Transistors - Discussion
Discussion Forum : Bipolar Junction Transistors - General Questions (Q.No. 14)
14.
Refer to this figure. The value of VBE is:
Discussion:
2 comments Page 1 of 1.
Mohammed Arif Rana said:
1 decade ago
Apply KVL.
vbb - ibrb - vbc = 0.
5-ib5k-0.7 = 0.
Ib = 0.86 mA.
Now apply kvl to identify the value of vbe.
vbb-ibrb-vbe = 0.
5-0.86*5-vbe = 0 .
vbe = 0.7 volt.
vbb - ibrb - vbc = 0.
5-ib5k-0.7 = 0.
Ib = 0.86 mA.
Now apply kvl to identify the value of vbe.
vbb-ibrb-vbe = 0.
5-0.86*5-vbe = 0 .
vbe = 0.7 volt.
(1)
Sreeyush Sudhakaran said:
1 decade ago
VBE=VB-VE
VB=0.7 for NPN
VE= IExRE here RE=0 ie,VE=0V
VBE=0.7-0 = 0.7V
VB=0.7 for NPN
VE= IExRE here RE=0 ie,VE=0V
VBE=0.7-0 = 0.7V
(1)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers