Electronic Devices - Bipolar Junction Transistors - Discussion
Discussion Forum : Bipolar Junction Transistors - General Questions (Q.No. 25)
25.
A 35 mV signal is applied to the base of a properly biased transistor with an r'e = 8 
and RC = 1 k. The output signal voltage at the collector is:
and RC = 1 k. The output signal voltage at the collector is:Discussion:
11 comments Page 1 of 2.
Rohine said:
3 years ago
Why it is 1000/8? As per question it is 1 K/8.
(2)
Diellza said:
5 years ago
Voltage gain is Av=Rc/r'e and Vout=Av*Vb.
Vout=1000/8 * 0.035 = 4.375 V.
Vout=1000/8 * 0.035 = 4.375 V.
Ganga said:
5 years ago
@Tushraj
vin =35mv voltage units volts and current units ampers.
vin =35mv voltage units volts and current units ampers.
TushRaj said:
6 years ago
@Sreenu @Asim basha.
But ib is 35mv how you take it vin?
But ib is 35mv how you take it vin?
Geeta said:
7 years ago
Thank you all for explaining it.
Ravi said:
8 years ago
Thank you everyone for explaining the answer.
Sreenu said:
9 years ago
Vgain = Rc/re.
Vo/Vin = Rc/re.
Vo = Vin * Rc/re.
Vo = 35 * 10^-3 * 1000/8.
Then, Vo = 4.375V.
Vo/Vin = Rc/re.
Vo = Vin * Rc/re.
Vo = 35 * 10^-3 * 1000/8.
Then, Vo = 4.375V.
(2)
Asim Basha said:
1 decade ago
Voltage gain in any transistor = Gm*Rc where Gm = 1/re.
Output voltage = Input voltage*Gain.
= 35*10^(-3)*1000/8.
Vo = 4.375V.
Output voltage = Input voltage*Gain.
= 35*10^(-3)*1000/8.
Vo = 4.375V.
(1)
Bini Jinesh said:
1 decade ago
Voltage gain A = Collector Resistance/ac emitter resistance.
So, Output/35 mv = 1K/8,
Output = 35/8 = 4.375.
So, Output/35 mv = 1K/8,
Output = 35/8 = 4.375.
Vinayak said:
1 decade ago
Please some one explain.
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