Electronic Devices - Bipolar Junction Transistors - Discussion
Discussion Forum : Bipolar Junction Transistors - General Questions (Q.No. 13)
13.
A BJT has an IB of 50 
A and a 
DC of 75; IC is:
A and a DC of 75; IC is:Discussion:
1 comments Page 1 of 1.
Shyam kishore said:
1 decade ago
Beta DC = Ic/Ib.
=> Ic= Beta DC*Ib.
=> Ic = 50Ua*75.
=>3750Ua.
or 3.75mA.
=> Ic= Beta DC*Ib.
=> Ic = 50Ua*75.
=>3750Ua.
or 3.75mA.
(1)
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