Electronic Devices - Basic Op-Amp Circuits - Discussion
Discussion Forum : Basic Op-Amp Circuits - General Questions (Q.No. 6)
6.
Refer to the given figure. What is the output voltage?
Discussion:
13 comments Page 1 of 2.
Debadutta said:
1 decade ago
Someone please explain.
Shahir said:
1 decade ago
Since + terminal is at low potential than the - ve terminal the output is -vsat.
Pkd said:
1 decade ago
Is it a comparator? if yes then the output is zero.
Mohanapriya.N said:
1 decade ago
The output is equal or greater than supply voltage it is called saturation. Here the output voltage is inverting output (negative). This is greater than supply (-2V). Hence this answer in correct.
Tanay said:
1 decade ago
Here -2V is applied to the noninverting terminal. Therefore the output must be -2V. So I think the answer is incorrect.
Charu said:
1 decade ago
Is it necessary or not to give Vref? is this circuit behave like zero crossing detector?
Krishna said:
1 decade ago
Vout = A(V+ - V-).
V+ = Voltage at non inverting terminal.
V- = Voltage at non inverting terminal.
When V+>V-,Vout = +Vsat.
V+<V-,Vout = -Vsat.
V+ = Voltage at non inverting terminal.
V- = Voltage at non inverting terminal.
When V+>V-,Vout = +Vsat.
V+<V-,Vout = -Vsat.
Dhanpat sharna said:
10 years ago
Output between the -vsat/vsat then v inverting is zero vot lies +- sat.
Rupesh said:
9 years ago
Non inverting comparator conditions:
When Vin>Vref = +Vsat,
When Vin<Vrff = -Vsat.
In problem -2<0 then answer is -Vsat.
When Vin>Vref = +Vsat,
When Vin<Vrff = -Vsat.
In problem -2<0 then answer is -Vsat.
Bhuvana said:
8 years ago
Input voltage is less than reference voltage so the output voltage must be -vsat.
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