Electronic Devices - Basic Op-Amp Circuits - Discussion
Discussion Forum : Basic Op-Amp Circuits - General Questions (Q.No. 7)
7.
If an op-amp comparator has a gain of 100,000, an input difference of 0.2 mV above reference, and a supply of 
12 V, the output will be
12 V, the output will beDiscussion:
11 comments Page 1 of 2.
Kaustav said:
4 years ago
No 10^6*0.2*10^-3 will give 200 v and the max output is 12 v.
So it's option B.
So it's option B.
Mahitha said:
5 years ago
Gain = vo/vi
Vo = gain*vi
Vo = 100000*0.2*10^-3
Vo = 20v
As it is crossing more than the power supply we do not consider 20 v and the max output should be of only 12 v so the answer is 12.
Vo = gain*vi
Vo = 100000*0.2*10^-3
Vo = 20v
As it is crossing more than the power supply we do not consider 20 v and the max output should be of only 12 v so the answer is 12.
Ninad said:
6 years ago
Vdiff = V+ - V-;
Here V+ dominates since Vdiff = +Ve.
As Non-inverting terminal dominates, the voltage does to +Vsat.
Here V+ dominates since Vdiff = +Ve.
As Non-inverting terminal dominates, the voltage does to +Vsat.
Luna choudhury said:
7 years ago
How to solve this?
Britto said:
7 years ago
Here the supply is only 12V. So the max Vo after the gain is only 12V.
Chhoti said:
7 years ago
How to solve this? Please anyone explain.
Rhagul mahadevan said:
7 years ago
In case of comparator if vin >0 [it means 0.2 is greater than reference] then vo is +vs[12v] and if vin<0 then vo will be -12 v.
Kshitij said:
8 years ago
12V is the wrong answer as the max output voltage is = 90% of 12 equal to 10.8~11V.
Nandini said:
8 years ago
What is the equation we have to use here?
Scott said:
1 decade ago
Since it is a comparator, if Voltage in (V+) is greater than the reference voltage, the output is the voltage in. if not, it is 0. (or the voltage at V-)
and this voltage is .2 mV greater than the reference
and this voltage is .2 mV greater than the reference
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