Electronic Devices - Amplifier Frequency Response - Discussion
Discussion Forum : Amplifier Frequency Response - General Questions (Q.No. 27)
27.
Halving the power corresponds to a ________ dB ________.
Discussion:
1 comments Page 1 of 1.
Shogun ShiShi said:
7 years ago
10log(x) = power.
20log(x) = voltage.
10log(1/2) = (-)3.0103.
(-)=decrease.
20log(x) = voltage.
10log(1/2) = (-)3.0103.
(-)=decrease.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers