Electronic Devices - Active Filters - Discussion
Discussion Forum : Active Filters - General Questions (Q.No. 6)
6.
Refer to the given figure. This circuit is known as a ________ filter, and the fc is ________.
Discussion:
3 comments Page 1 of 1.
Bhagat Gujjar said:
8 years ago
As we know that when R is grounded it is high Filter and when C is grounded it is Low pass Filter.
And f = 1/2*π*r*c= 15.9khz.
And f = 1/2*π*r*c= 15.9khz.
(1)
Bhaskar said:
1 decade ago
fc=1/2*pi*rc where rc equal r1c1 or r2c2.
So, fc= 1/2*3.14*100*.1*10^(-6)= 15.9 khz.
So, fc= 1/2*3.14*100*.1*10^(-6)= 15.9 khz.
Honey said:
1 decade ago
From figure it is clear that it is a high-pass and
fc=1/(2*pi*c1*c2*r1*r2)
fc=1/(2*pi*c1*c2*r1*r2)
(1)
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