Electrical Engineering - Voltage, Current and Resistance - Discussion

Discussion Forum : Voltage, Current and Resistance - General Questions (Q.No. 18)
18.
If there is 6 A of current through the filament of a lamp, how many coulombs of charge move through the filament in 1.75 s?
10.5 C
105 C
3.4 C
34 C
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
12 comments Page 1 of 2.

Mukesh said:   10 years ago
Come on guys as we know that I = Coulomb/Second.

But in this question we have to find the charge, simply take out the charge and multiply the time/current.

C = T*I = 1.75*6 = 10.5.

Gina said:   1 decade ago
Algebra:

i = q/t.

Multiply both sides by t to isolate q, so,

(t)*i = q/t* (t).

The t cancels itself out on the right side. So,

(t)*i = q.
1.75*6 = q.
10.5 = q.

RAGHU VENNA said:   1 decade ago
As per formulae Charge(q)=current/time(sec)=i/t
so i = q/t
q = i*t=(6*1.75)
q = 10.5

Kartheek said:   9 years ago
Please anyone help me.

After fraction multiplication how can we decide to put dot?

Sreekanth said:   9 years ago
Current = Charge / Time i.e q / t,

Q = i * t,

Q = 6 * 1.75,

Q = 10.5 c.
(7)

Muhammad Tahir said:   1 decade ago
Elaborate please. How could q = current/time be equal to i = q/t sir?

Munna said:   9 years ago
It's impossible q = i/t not equals i = q/t.
q = i/t equal i = q * t.

Devi said:   10 years ago
Can anyone explain me how it's possible q=i/t equals i=q/t?

Chandu said:   1 decade ago
I didn't understand can any one be specific how i = q/t?

Madhan said:   1 decade ago
First line tells q=i/t then next line its i=q/t?


Post your comments here:

Your comments will be displayed after verification.