Electrical Engineering - Voltage, Current and Resistance - Discussion
Discussion Forum : Voltage, Current and Resistance - General Questions (Q.No. 12)
12.
Eight-tenths coulomb passes a point in 4 s. The current in amperes is
Discussion:
42 comments Page 3 of 5.
Surajit said:
1 decade ago
Q = 8/10
t = 4 s
Now current i = Q / t that means current=charge/time
i = (8/10)/4
i = 2/10;
i = 0.2 A
t = 4 s
Now current i = Q / t that means current=charge/time
i = (8/10)/4
i = 2/10;
i = 0.2 A
Saroj said:
8 years ago
q =it.
=> i = q/t.
q = 8/10 = 0.8, t=4.
i = 0.8/4 = 0.2.A.
=> i = q/t.
q = 8/10 = 0.8, t=4.
i = 0.8/4 = 0.2.A.
Yevuna Frederick said:
8 years ago
You are right @Prashant.
Suresh said:
8 years ago
Thank you @Prashant.
Ashutosh said:
1 decade ago
Q = 8/10 = 0.8.
t = 4s.
I = Q/t.
= 0.8/4
= 0.2A.
t = 4s.
I = Q/t.
= 0.8/4
= 0.2A.
Sonal ghadge said:
9 years ago
Thank you @Prashant & @Jagadesh.
Srinath prabhu said:
9 years ago
Thank you @Jagadesh.
AVADHESH KUMAR said:
1 decade ago
Yes q=i*t means charge=current*time.
So q=8/10 &t=4s.
So i=q/t=8/10/4=0.2 A.
So q=8/10 &t=4s.
So i=q/t=8/10/4=0.2 A.
Chandan said:
9 years ago
@Prashant.
Good explanation, thank you.
Good explanation, thank you.
Jagadesh said:
10 years ago
Current i = dq/dt.
Here the charge q = 8/10.
Time t = 4s.
Here as the charge is not changing with time.
Therefore the current equation becomes at instantaneous i = q/t.
i = (8/10)/4.
i = 8/40 = 2/10.
i = 0.2 A.
Here the charge q = 8/10.
Time t = 4s.
Here as the charge is not changing with time.
Therefore the current equation becomes at instantaneous i = q/t.
i = (8/10)/4.
i = 8/40 = 2/10.
i = 0.2 A.
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