Electrical Engineering - Voltage, Current and Resistance - Discussion
Discussion Forum : Voltage, Current and Resistance - General Questions (Q.No. 12)
12.
Eight-tenths coulomb passes a point in 4 s. The current in amperes is
Discussion:
42 comments Page 2 of 5.
Veeru said:
1 decade ago
Total charge Q = I*T.
Thereforre I=Q/T.
I=(8/10)/4
=(8/10)*(1/4)
=2/10
I=0.2A.
Thereforre I=Q/T.
I=(8/10)/4
=(8/10)*(1/4)
=2/10
I=0.2A.
AVADHESH KUMAR said:
1 decade ago
Yes q=i*t means charge=current*time.
So q=8/10 &t=4s.
So i=q/t=8/10/4=0.2 A.
So q=8/10 &t=4s.
So i=q/t=8/10/4=0.2 A.
Prashant said:
1 decade ago
Q = 8/10 given;
t = 4 s
Now current i = Q / t
i = (8/10)/4
i = 2/10;
i = 0.2 A
t = 4 s
Now current i = Q / t
i = (8/10)/4
i = 2/10;
i = 0.2 A
(1)
Habeeb said:
1 decade ago
Given that q = 8/10.
And t = 4s.
We know that i = q/t.
i = (0.8)/4 = 0.2 A.
And t = 4s.
We know that i = q/t.
i = (0.8)/4 = 0.2 A.
Mohd imran said:
7 years ago
I have a doubt. How come 8/10?
Why not 8*10?
Please give the answer.
Why not 8*10?
Please give the answer.
(1)
ZUBAIR AHAMED said:
1 decade ago
Charge/coulombs Q = I*T.
So I = Q/T.
I = 8/(10*4).
I = 0.2A.
So I = Q/T.
I = 8/(10*4).
I = 0.2A.
Saroj said:
8 years ago
q =it.
=> i = q/t.
q = 8/10 = 0.8, t=4.
i = 0.8/4 = 0.2.A.
=> i = q/t.
q = 8/10 = 0.8, t=4.
i = 0.8/4 = 0.2.A.
Ashutosh said:
1 decade ago
Q = 8/10 = 0.8.
t = 4s.
I = Q/t.
= 0.8/4
= 0.2A.
t = 4s.
I = Q/t.
= 0.8/4
= 0.2A.
Sachin nityanand nikose said:
8 years ago
I = q/t.
I = 8/10/4,
I = 8/10*4,
I = 8/40,
I = 0.2Amp.
I = 8/10/4,
I = 8/10*4,
I = 8/40,
I = 0.2Amp.
(11)
Praveen Raj said:
1 decade ago
Q = 8/10 = 0.8.
T = 4.
I = Q/T.
I = 0.8/4.
I = 0.2.
T = 4.
I = Q/T.
I = 0.8/4.
I = 0.2.
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