Electrical Engineering - Voltage, Current and Resistance - Discussion
Discussion Forum : Voltage, Current and Resistance - General Questions (Q.No. 12)
12.
Eight-tenths coulomb passes a point in 4 s. The current in amperes is
Discussion:
42 comments Page 2 of 5.
Yevuna Frederick said:
8 years ago
You are right @Prashant.
Suresh said:
8 years ago
Thank you @Prashant.
Noshair said:
8 years ago
Q = 8/10 = 0.8.
T = 4.
I = Q/T.
I = 0.8/4.
I = 0.2.
T = 4.
I = Q/T.
I = 0.8/4.
I = 0.2.
(2)
Sonal ghadge said:
9 years ago
Thank you @Prashant & @Jagadesh.
Srinath prabhu said:
9 years ago
Thank you @Jagadesh.
Spoorti said:
9 years ago
Thank you @Ashutosh.
Chandan said:
9 years ago
@Prashant.
Good explanation, thank you.
Good explanation, thank you.
Jagadesh said:
10 years ago
Current i = dq/dt.
Here the charge q = 8/10.
Time t = 4s.
Here as the charge is not changing with time.
Therefore the current equation becomes at instantaneous i = q/t.
i = (8/10)/4.
i = 8/40 = 2/10.
i = 0.2 A.
Here the charge q = 8/10.
Time t = 4s.
Here as the charge is not changing with time.
Therefore the current equation becomes at instantaneous i = q/t.
i = (8/10)/4.
i = 8/40 = 2/10.
i = 0.2 A.
Vivek Dwivedi said:
10 years ago
q = 8/10 = 0.8.
t = 4.
Current (i) = q/t.
i = 0.8/4 = 0.2.
That is a correct answer.
t = 4.
Current (i) = q/t.
i = 0.8/4 = 0.2.
That is a correct answer.
Manpreet choudhary said:
10 years ago
All friends give this answer wisely and correctly.
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