Electrical Engineering - Transformers - Discussion

Discussion Forum : Transformers - General Questions (Q.No. 1)
1.
What kVA rating is required for a transformer that must handle a maximum load current of 8 A with a secondary voltage of 2 kV?
4 kVA
0.25 kVA
16 kVA
8 kVA
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
121 comments Page 8 of 13.

Jitendranath panda said:   1 decade ago
s/v - 2kv*8A = 16kva.

So 16kva or higher power transformer required.

MOHAMED MANSOOR said:   1 decade ago
V2*I2=2*8=16.
Here load current=I2=8A

Siri said:   1 decade ago
Here how we can assume power-factor values?

Kedar apkar said:   1 decade ago
p=vicosQ for single phase p= root3*VICosQ for three phase
Consider 0.95 PF For transformer
0.80 PF for generator
p=2000*8*0.95
= 15200=15.2KW
So PF = KW/KVA we need KVA rating
KVA= KW/PF
= 15.2/0.95=16KVA.

L P RAI said:   1 decade ago
We know
E2/E1=N2/N1=I1/I2
>E2/E1= I1/I2
>E1*I1=E2*I2
=2Kv *8A
=16 KVA

We should note (in this question) the rating of transformer meanse input kva rating the out put voltage and current i.e load current is already given.

Mohd tajammul akhter said:   1 decade ago
The transformer rating in kva when 2kv is multiplied by 8a then it become 16kva.

Bhushan Kumbhalkar said:   1 decade ago
KVA=V1*i1=V2*i2.

Therefore here, V2=2KV, i2=8Amp.

Then, KVA=V2*i2.

KVA=2*8;

KVA=16.

Virendra mandloi said:   1 decade ago
Why we note transformer's power in kva or mva? but why we do not in khva or mhva?

P.H.Hussain said:   1 decade ago
We know that,
Power P=voltage*current
P=2*8=16kw (or) 16kVA.

Priya said:   1 decade ago
Q=v*i*10^-3
Q=20000*8*10^-3
Q=16kva


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