Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 1)
1.
What kVA rating is required for a transformer that must handle a maximum load current of 8 A with a secondary voltage of 2 kV?
Discussion:
121 comments Page 6 of 13.
SASI said:
9 years ago
Friends, this is my interview question.
Please explain transformer with ohms law.
Please explain transformer with ohms law.
Virendra mandloi said:
1 decade ago
Why we note transformer's power in kva or mva? but why we do not in khva or mhva?
Mohd tajammul akhter said:
1 decade ago
The transformer rating in kva when 2kv is multiplied by 8a then it become 16kva.
Sindhuri said:
1 decade ago
Power = Voltage*Current.
Power on load side = V2*I2.
Here P = 2kv*8A.
=16kvA.
Power on load side = V2*I2.
Here P = 2kv*8A.
=16kvA.
Anshuman said:
1 decade ago
Power = Voltage*Current.
Power on load side = V2*I2.
Here P = 2kv*8A.
=16kvA.
Power on load side = V2*I2.
Here P = 2kv*8A.
=16kvA.
Rabindra Das said:
1 decade ago
Transformer always rating in KVA that means voltage *current.
So 8*2 = 16 KVA.
So 8*2 = 16 KVA.
Pravin said:
1 decade ago
But friend transformer reading in kva.
That means p = vi cos phi power factor.
That means p = vi cos phi power factor.
Ravikant said:
1 decade ago
Why the losses (c&i) are calculaed in kva of transformer why not in kw?
Sanju said:
1 decade ago
We know that t/f raiting is KVA
So,
kva=kilo volt*A(amp..)
2*8=16KVA
So,
kva=kilo volt*A(amp..)
2*8=16KVA
POOJA GUPTA said:
1 decade ago
WE KNOW THAT,
POWER ON LOAD SIDE,
SO,
P = V2*I2.
P = 8A*2KV = 16 KVA.
POWER ON LOAD SIDE,
SO,
P = V2*I2.
P = 8A*2KV = 16 KVA.
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