Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 1)
1.
What kVA rating is required for a transformer that must handle a maximum load current of 8 A with a secondary voltage of 2 kV?
Discussion:
121 comments Page 3 of 13.
Azhagu said:
1 decade ago
Output = Max I x Secondary voltage
= 8A *2000 V
= 16 KVA.
= 8A *2000 V
= 16 KVA.
Chakri said:
1 decade ago
kVA=(Secondary Voltage)*(Secondary Current)
=(2000*8)=16kVA
=(2000*8)=16kVA
A.Harish said:
1 decade ago
Load current means secondary current, already we know secondary voltage.
So output load is i*v=kva
i=8A and v=2KVA
So i*v=16kva.
So output load is i*v=kva
i=8A and v=2KVA
So i*v=16kva.
Paresh said:
1 decade ago
Why we rating in kva?
Rahul Prajapati said:
1 decade ago
Because all losses ( core losses and copper losses ) are calculated in kva. That is why transformer is rated in kva.
K.vijay anand said:
1 decade ago
KVA = ( VOLTS * AMP )/1000 = ( 2000 * 8 ) /1000 = 16
Gautam said:
1 decade ago
KVA=(V*A)/1000=>(16000/8)=>16
KVA=16
KVA=16
Piyush said:
1 decade ago
Because of we find kva that means we have to multiply with current so that.
Ans= 2kv*8 (given) =16kva.
Ans= 2kv*8 (given) =16kva.
Venkatesh said:
1 decade ago
Suppose 2kv is given as 2v then what is the answer.
Navneet kumar said:
1 decade ago
kva
=volt*ampere/1000
=2000*8/1000
=16
=volt*ampere/1000
=2000*8/1000
=16
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