Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 1)
1.
What kVA rating is required for a transformer that must handle a maximum load current of 8 A with a secondary voltage of 2 kV?
Discussion:
121 comments Page 2 of 13.
UJJAWAL PATLE said:
9 years ago
v * A = 2000 * 8\1000 = 16kva.
Venkatesh badgujar said:
9 years ago
It is 16 volt * current.
Sachin said:
9 years ago
@All.
Thanks for the explanation.
Thanks for the explanation.
Gyanprakash said:
9 years ago
Thank you for all the solution and explanation.
Jayadeva said:
9 years ago
The output power of transformer is depending pf, so it is not to be rated for kw.
ex, if v = 10V.
A = 2A.
pf = 0.8.
P = v * i * pf .
p = 10 * 2 * 0.8 ,
p = 16w.
And
p = v * i.
p = 10 * 2,
p = 20.
ex, if v = 10V.
A = 2A.
pf = 0.8.
P = v * i * pf .
p = 10 * 2 * 0.8 ,
p = 16w.
And
p = v * i.
p = 10 * 2,
p = 20.
Sree said:
9 years ago
kva rating = v × i = 2000 × 8 = 16000.
SASI said:
9 years ago
Friends, this is my interview question.
Please explain transformer with ohms law.
Please explain transformer with ohms law.
Sasenthiran said:
9 years ago
Kv * A = kvA,
8 * 2 = 16.
8 * 2 = 16.
Sanjay verma said:
9 years ago
How to find PF?
Rakesh kumar said:
9 years ago
kVA rating = EI. Here 8 amp and secondary voltage are given then multiply both then we
get 16.
get 16.
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