Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 16)
                   
                                       
                                16.
A certain amplifier has 600 
 internal resistance looking from its output. In order to provide maximum power to a 4 
 speaker, what turns ratio must be used in the coupling transformer?
 
                                    
 internal resistance looking from its output. In order to provide maximum power to a 4 
 speaker, what turns ratio must be used in the coupling transformer?Discussion:
19 comments Page 2 of 2.
                
                        ShaijuTS said: 
                         
                        1 decade ago
                
                Pow((Ns/Np),2) = Zs/Zp
ie. pow(k,2) = 4/600
k=sqrt(4/600)
k=0.08
                ie. pow(k,2) = 4/600
k=sqrt(4/600)
k=0.08
                        Rakesh alliwar said: 
                         
                        9 years ago
                
                Yes, 0.08 is the correct answer.
                
                        E.sravani said: 
                         
                        1 decade ago
                
                Power = i^2r.
Input power = i1^2r1 = i1^2(600).
Output power = i2^2r2 = i2^2(4).
P(in) = P(out).
i1^2(600) = i2^2(4).
K^2 = (4/600) {(i1/i2)^2 = k^2}.
K = 0.08.
                Input power = i1^2r1 = i1^2(600).
Output power = i2^2r2 = i2^2(4).
P(in) = P(out).
i1^2(600) = i2^2(4).
K^2 = (4/600) {(i1/i2)^2 = k^2}.
K = 0.08.
                        Ashim said: 
                         
                        1 decade ago
                
                Turns ratio K = N2/N1= sqrt (R2/R1) = sqrt (4/600) = 0.08.
                
                        Love said: 
                         
                        1 decade ago
                
                But it is asked to determine turn ratio = 1/K.
                
                        Akash.bhure said: 
                         
                        1 decade ago
                
                Internal resistance(R1)=600 ohms.
Output speaker(R2)=4 ohms.
R1 = R2/K^2.
600 = 4/K^2.
K^2 = 4/600 = 0.0066.
K = sqrt(0.0066) = 0.081.
                Output speaker(R2)=4 ohms.
R1 = R2/K^2.
600 = 4/K^2.
K^2 = 4/600 = 0.0066.
K = sqrt(0.0066) = 0.081.
                        Manish said: 
                         
                        1 decade ago
                
                V2/I2 = 4.
V1/I1 = 600.
V2xI1/V1xI2 = 4/600.
N2 = 4/600N1 = 0.08.
                V1/I1 = 600.
V2xI1/V1xI2 = 4/600.
N2 = 4/600N1 = 0.08.
                        Siri said: 
                         
                        1 decade ago
                
                @Saritha.
Transformation ratio is unit less quantity.
Not measured in ohms.
                Transformation ratio is unit less quantity.
Not measured in ohms.
                        Saritha said: 
                         
                        1 decade ago
                
                Here,
Load resistance(destination)=4 ohms
Source resistance=600 ohms
  
k=(r2/r1)^0.5
=(4/600)^0.5
=0.0816
k=0.0816 ohms
                Load resistance(destination)=4 ohms
Source resistance=600 ohms
k=(r2/r1)^0.5
=(4/600)^0.5
=0.0816
k=0.0816 ohms
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