Electrical Engineering - Transformers - Discussion

Discussion Forum : Transformers - General Questions (Q.No. 24)
24.
A transformer has a 1:6 turns ratio and a secondary coil load resistance of 470 . The load resistance as seen by the source is
1.3
7.8
78
13
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
15 comments Page 1 of 2.

Walid said:   7 years ago
Guys it's turns ratio so n1/n2 =1/6 = 0.16.

And R1=R2*(turns ratio)^2 =470 * 0.025 = 13.
(3)

Narasimha Reddy said:   8 years ago
I totally confused.

Is it n1/n2 or n2/n1?
(2)

Durgaprasad said:   1 decade ago
K=N2/N1
K=6/1=6
R1=470
R2=R1/(K^2)
SO 470/36=13.06OHMS
(1)

Majid Mahmood said:   6 years ago
@Reddy.

1/6 = 0.166.

When ratio is less than one mean step up use v2/v1 otherwise use v1/v2.
(1)

Siva said:   1 decade ago
n1/n2=(r1/r2)^2

Darwin said:   1 decade ago
Given, N(pri):N(sec) = 1:6
R = 470 ohm
So, Relective Resistance = [(1/n)^2]*R = 470/36 = 13.055
Where, n = N(sec)/N(pri) = 6

Patil said:   1 decade ago
Is transformer ratio always N2/N1?

Kazi jasimuddin said:   10 years ago
If the relation between turns ratio and resistance is n1/n2=sqrt (r1/r2) then answer will be 78.

Basu patil said:   9 years ago
Thank you lot indiabix. Friends I have doubt, is transformer ratio is constant or not? because I have seen.

Two types i.e. N2/N1 And N1/N2. Which one is correct ? please clear my confusion.

Sudhir said:   9 years ago
Zin or Zsource = ZL(load impedance)/n^2. Here n is turned ratio.


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