Electrical Engineering - Time Response of Reactive Circuits - Discussion
Discussion Forum : Time Response of Reactive Circuits - General Questions (Q.No. 11)
11.
If the capacitor in an integrator becomes leaky,
Discussion:
5 comments Page 1 of 1.
Anu said:
7 years ago
t=RC, c changes the time constant changes.
The leakage of the capacitor means discharging soo capacitance reduces the time constant reduces. Across the output, due to discharge in a capacitor, the o/p is changing. And also amplitude changes.
The leakage of the capacitor means discharging soo capacitance reduces the time constant reduces. Across the output, due to discharge in a capacitor, the o/p is changing. And also amplitude changes.
Bhargav said:
9 years ago
Is that term leaky won't indicate about leakage resistance?
Ghanu said:
1 decade ago
How all of above be the answer can somebody please explain?
Havish said:
1 decade ago
Vo= -(1/C)*integral(Vi/R)dt + K
This is the output of the integrator
As the leakage current flows in the capacitor,
The integration term changes because the charge is leaking out.
Hence the voltage amplitude changes.
This is the output of the integrator
As the leakage current flows in the capacitor,
The integration term changes because the charge is leaking out.
Hence the voltage amplitude changes.
Arya said:
1 decade ago
How amplitude get reduce?
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