Electrical Engineering - Time Response of Reactive Circuits - Discussion
Discussion Forum : Time Response of Reactive Circuits - General Questions (Q.No. 22)
22.
What is the highest frequency contained in a pulse that has a rise and fall time equal to 10 microseconds (10
s)?

Discussion:
15 comments Page 1 of 2.
Mkhan.q said:
4 years ago
Bandwidth can be calculated by using the formula.
Bandwidth= 0.35/rise time.
Here rise time is 10 microseconds.
Hence;
Bandwidth= 0.35/10x10^-6,
Bandwidth= 35k Hertz.
Bandwidth= 0.35/rise time.
Here rise time is 10 microseconds.
Hence;
Bandwidth= 0.35/10x10^-6,
Bandwidth= 35k Hertz.
(1)
Raghu said:
1 decade ago
1/t = 1/10 micro = 100 kHz.
Sri said:
1 decade ago
Please explain how is the answer A?
Manoj said:
1 decade ago
1/10micro = 100k is the answer.
Vbs said:
1 decade ago
How 35 khz?
BANU said:
10 years ago
1/t = 1/(10*10^-6) = 100,000 k.
Here, 1 khz = 1000 hz.
So 100 khz.
Here, 1 khz = 1000 hz.
So 100 khz.
Ranjith kumar said:
10 years ago
tr = 0.35/bandwidth.
Rupesh kerketta said:
10 years ago
How it's 35?
Anil said:
9 years ago
Answer should be 100 kHz.
Sewak said:
9 years ago
According to me,
Rise Time 10 micro Sec, Fall time 10 micro Sec.
So complete cycle time is 20 micro Sec.
Frequency = 1/Time span of 1 cycle.
Frequency = 1/20 micro Sec,
Frequency = 1/20 * 10^-6,
Frequency = 50 KHz.
Rise Time 10 micro Sec, Fall time 10 micro Sec.
So complete cycle time is 20 micro Sec.
Frequency = 1/Time span of 1 cycle.
Frequency = 1/20 micro Sec,
Frequency = 1/20 * 10^-6,
Frequency = 50 KHz.
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