Electrical Engineering - Time Response of Reactive Circuits - Discussion
Discussion Forum : Time Response of Reactive Circuits - General Questions (Q.No. 12)
12.
Referring to the above figure, determine the voltage level that the output will reach during the pulse.
Discussion:
12 comments Page 1 of 2.
Adii said:
5 years ago
Agree, the answer is 15 volts.
(1)
Rajnikanth said:
6 years ago
My answer is also 15 volts.
(1)
Chinnu said:
8 years ago
My answer is 15 volts.
(1)
Alex said:
8 years ago
I have found V=15V too.
(1)
Anonymous said:
9 years ago
What should be the correct answer?
Sewak said:
9 years ago
Here L1=750mH, R1= 680Kohm.
Time constant (T) in LR circuit is L/R = 750 * 10^-3 / 750 * 10^3,
T =1.10 * 10^-6 (1.10 micro Sec).
Time duration of pulse is t =1/1Khz,
t = 1 / 1000 Hz,
t = 1 * 10^-3,
t = 1 milli Sec.
V = Vo ( 1 - e^(-t/T)).
V = 15 ( 1 - e^(- 1* 10^-3 / 1 * 10^3)).
V = 15 ( 1 - e^(- 1* 10^-6)).
V = 15 ( 1 - 0) AS e^(- 1* 10^-6) = nearly zero.
V = 15.
SO, the answer should be B.
Time constant (T) in LR circuit is L/R = 750 * 10^-3 / 750 * 10^3,
T =1.10 * 10^-6 (1.10 micro Sec).
Time duration of pulse is t =1/1Khz,
t = 1 / 1000 Hz,
t = 1 * 10^-3,
t = 1 milli Sec.
V = Vo ( 1 - e^(-t/T)).
V = 15 ( 1 - e^(- 1* 10^-3 / 1 * 10^3)).
V = 15 ( 1 - e^(- 1* 10^-6)).
V = 15 ( 1 - 0) AS e^(- 1* 10^-6) = nearly zero.
V = 15.
SO, the answer should be B.
(2)
YUTHIKA said:
1 decade ago
V = 15*(1-EXP^( 680*10^3/750*10^-3) = 9.48(approximately).
Keerthi said:
1 decade ago
@Philip.
How did you get tc=0.63?
Answer @Sumitha please do the calculations for this problem, not for any other questions. How did you get tR/L=1?
How did you get tc=0.63?
Answer @Sumitha please do the calculations for this problem, not for any other questions. How did you get tR/L=1?
Nyce said:
1 decade ago
During the pulse means 1 time constant?
Ram krishna said:
1 decade ago
@Sumita.
Please tell me how you find value of tR/L as 1?
Please tell me how you find value of tR/L as 1?
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