Electrical Engineering - Time Response of Reactive Circuits - Discussion
Discussion Forum : Time Response of Reactive Circuits - General Questions (Q.No. 6)
6.
Referring this circuit, determine the maximum output voltage when a single pulse is applied as shown. The total resistance is 60 
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Discussion:
9 comments Page 1 of 1.
Mamad said:
4 years ago
Get XL by 2pieFL = 50π
str 50π to A.
then get V = 30(1-e^-A/60),
V = 27.81 its near 27.33.
str 50π to A.
then get V = 30(1-e^-A/60),
V = 27.81 its near 27.33.
(3)
Prati said:
7 years ago
The voltage across an inductor is Ve^-tR/L and this formula we get 2.72 V, and the rest will appear across the resistance i.e. 27.
(1)
RAJI said:
4 years ago
Thank you Everyone.
(1)
Ravi said:
1 decade ago
Since the frequency of the input is low the reactance of the inductor will be low. so the R>X and hence we will get max voltage across resistance.
The exact value of voltage i can't say as something is wrong with question ;)
The exact value of voltage i can't say as something is wrong with question ;)
Brad said:
1 decade ago
T = 1/F.
Er = E(1-e^(-R/L)(1/F0)).
Er = 30(1-e^(-60/200m)(1/125).
Er = 27.28V.
Er = E(1-e^(-R/L)(1/F0)).
Er = 30(1-e^(-60/200m)(1/125).
Er = 27.28V.
Shainaz said:
1 decade ago
@Brad.
It is the voltage across the inductor but here it is asked to.
Find out output voltage i.e, voltage across resistor.
I think answer should be 2.67v.
It is the voltage across the inductor but here it is asked to.
Find out output voltage i.e, voltage across resistor.
I think answer should be 2.67v.
Arun said:
1 decade ago
Vl = v*e^-(R/L)t.
v - Applied voltage.
Vl - Voltage drop across inductor during transient.
v - Applied voltage.
Vl - Voltage drop across inductor during transient.
UDAY KUMAR YADAV said:
10 years ago
Ya but in case of rl circuit.
v = vm*e^-(R/L)T is there, but through this we can't get desire answer which is in option.
v = vm*e^-(R/L)T is there, but through this we can't get desire answer which is in option.
Elenic said:
5 years ago
From the rule, we can get the voltage across inductance, so when we subtract the inductance voltage from input voltage we can get the right answer.
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