Electrical Engineering - Time Response of Reactive Circuits - Discussion

Discussion Forum : Time Response of Reactive Circuits - General Questions (Q.No. 4)
4.
With an RL integrator, at the instant of the rising pulse edge,
all the input voltage is across the resistor
all the input voltage is across the inductor
63 percent of the input voltage is across the resistor
63 percent of the input voltage is across the inductor
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
3 comments Page 1 of 1.

Md. Sajedul Islam said:   8 years ago
When the pulse generator output goes high, a voltage immediately appears across the inductor in accordance with Lenz's law. The instantaneous current is zero, so the resistor voltage is initially zero.

At the top of the input pulse, the inductor voltage decreases exponentially and current increases. As a result, the voltage across the resistor increases exponentially. As in the case of the RC integrator, the output will be 63% of the final value in 1t.

Vimlesh patil said:   1 decade ago
Because just before the instant of rising pulse voltage capacitor was acting as a short ckt, and according to inductor property it will not allow sudden changes hence just after or at the instant of rising pulse voltage it remains in open circuit hence all the input voltage appears across the open circuit or across the inductor.

After a long time as inductor keeps on charging when it reaches steady state it will act as a short circuit and all the input voltage appears across the resistor.

Chinmaya ranjan moharana said:   1 decade ago
Why With an RL integrator, at the instant of the rising pulse edge, all the input voltage is across the inductor?

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