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Electrical Engineering - Time Response of Reactive Circuits - Discussion

Discussion Forum : Time Response of Reactive Circuits - General Questions (Q.No. 15)
Time Response of Reactive Circuits
15.
Referring this figure, on the falling edge,

the resistor voltage drops to –5 V and then goes back to zero exponentially
the resistor voltage jumps to –5 V and then goes back to zero exponentially
the capacitor voltage remains constant
the resistor voltage jumps to +5 V and then decreases exponentially to zero
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
2 comments Page 1 of 1.
Kimpoy said:   3 years ago
I got confused with the voltage jump and drop. Please, anyone, clarify it.
(1)
Tarique Jarwar said:   1 decade ago
The capacitor charges as +ve peak is received at +plate, the C charges and then it discharges as the impulse of +5V deceases through -ve plate providing -ve peak to resistor.
(1)
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