Electrical Engineering - Time Response of Reactive Circuits - Discussion
Discussion Forum : Time Response of Reactive Circuits - General Questions (Q.No. 3)
3.
Referring to Problem 5, how long will it take the capacitor to discharge if the internal resistance of the pulse source is 100 
?
?300 
s
s600 s
s900 s
s1.5 ms
Discussion:
16 comments Page 1 of 2.
AJAY said:
9 years ago
Please explain with the formula.
(1)
Vinod palaka said:
8 years ago
Explanation is need for this problem.
(1)
Sachin Kumar said:
3 years ago
Anyone, explain this in detail.
(1)
Anonymous said:
2 years ago
Final capacitor voltage=0 volt, after complete discharge.
Vc(t) = Vc(infinity)+(Vc(initial)-Vc(infinity))e^-t/RC---------eq(1)
Vc(t) = 0, Vc(infinity)=0,Vc(initial)=some volts calculated from question no 5, RC=100*1.5*10^-6.
Put all values in eq(1) and then find t.
Vc(t) = Vc(infinity)+(Vc(initial)-Vc(infinity))e^-t/RC---------eq(1)
Vc(t) = 0, Vc(infinity)=0,Vc(initial)=some volts calculated from question no 5, RC=100*1.5*10^-6.
Put all values in eq(1) and then find t.
(1)
Priyajit said:
9 years ago
How it is works?
Hussein said:
9 years ago
Please explain the solution.
Janu said:
9 years ago
Explain it.
Engineer said:
9 years ago
It seems the value of capacitance should be added.
Karshan Gagiya said:
6 years ago
Please Explain it.
Willson selva said:
6 years ago
Please explain it.
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