Electrical Engineering - Three-Phase Systems in Power Applications - Discussion

Discussion Forum : Three-Phase Systems in Power Applications - General Questions (Q.No. 13)
13.
If in a Y-connected ac generator, each phase voltage has a magnitude of 90 VRMS, what is the magnitude of each line voltage?
0 V
90 V
156 V
180 V
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
11 comments Page 1 of 2.

Vipul said:   7 years ago
In star connection.

line voltage =1.732*phase voltage.
= 1.732*90,
= 155.88,
~156.
(2)

Jagabandhu sahani said:   1 decade ago
In star connection line voltage lead phase voltage by 30 degree.

Line voltage = 90*1.732 = 155.88.

It is correct answer.

Shoaib Iqbal said:   1 decade ago
Vphase(max) = Vr.m.s/.707.

= 90/.707.

Vphase(max = 127.29 v.

Now in star connected networks.

V(line) = 1.732*V(phase).

= 1.732*127.29.

= 220 v.

I think it is the correct answer.
(3)

PRASHANT SINGH said:   1 decade ago
In Y connection line voltage lead phase voltage by 30 degree.

And line voltage = Vl*1. 732.

T.Pandey said:   1 decade ago
In star connection Vline = 1.732 x Vphase
So, Vline = 1.732x90 = 156v(approx.)

Samaya Sanjeevi said:   1 decade ago
In Y-connected system line voltage=sqrt(3)*phase voltage.

So VL=1.732*90=155.88=156V.

Sk saidulu said:   1 decade ago
In delta connected network,line and phase voltages are equal,where as line current = root 3 times of phase currents
90*1.732 = 156 v

Lavanya said:   1 decade ago
Line voltage=root 3 times of phase voltage in star connected, where as line currents and phase currents are equal.

In delta connected network,line and phase voltages are equal,where as line current = root 3 times of phase currents.

Tarnjeet Singh Seehra said:   1 decade ago
90*1.732 = 156 v

Sundar said:   1 decade ago
90 * sqrt(3) = 155.88 = 156.


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